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Consideration of a stage of switching of thyristors for a full-wave rectifier with centre tap and active - inductive load with infinite inductance

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  8. Match the English sentences with their Russian equivalents. Define the forms of the Gerund (Indefinite/Perfect/Active/Passive). Analyze the methods of translating the Gerund.
  9. Operation of a full-wave rectifier with a centre tap with an active load

 

Conditions: Ld = ¥, ra=0, La=0, 0 <a <

As there is inductance La connected in series with thyristor, a current iT can not change by jump. The current of the switching on thyristor will be increased from 0 up to Id and the current of the switching off thyristor decreases from Id up to 0, i.e. during the same time two thyristors of same group are on state. These phenomena names as a stage of a current commutation. Duration of the stage of switching terminates asan angle γ.

 

 

Figure 1.16

Let’s consider that VS1 is turned on just as a control pulse is applied and this moment should be a moment of a reference mark. VS2 is beginning to turn off.

During an interval γ iT1 is growing up from 0 to Id;

iT2 is growing down from Id to 0.

According to first Kirchhoff’s law

Id = iT1 + iT2

Since Ld = ¥ a load current have only a direct component; hence, an alternating component of thyristors’ currents flows through phases of the transformer and the thyristors witch are both turned on.

We should designate it as iC.

Then

iT1 = iC; iT2 = Id – iC;

Inductance of a branch of the thyristor

ха = wLa

According to 2-nd Kirchhoff’s law

iK = iT1

Let's discover γ from a condition:

At u = γ iT1 (γ) = Id

According to the theorem of the equivalent generator during the interval γ

 

 
 

 

 


Figure 1.17

Let's discover an average rectified voltage

 

where no-load EMF is

Commutating voltage drop is

 

From here, we could get an equation of the external characteristic

 

 


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